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$top (expression operator)

Definition

$top: New in version 8.3. :
Returns the top element within an array according to the specified sort order.

Note

Disambiguation

This page describes the $top expression operator. For the $top accumulator operator, see $top (accumulator operator).

Syntax

When used as an expression operator, $top has the following syntax:

{
   $top:
      {
         sortBy: <expression>,
         input: <expression>
      }
}

Field	Necessity	Description
sortBy	Required	Specifies the order of results. See Sort Behavior for more information on `sortBy` values.
input	Required	The array that `$top` evaluates.

Behavior

Sort Behavior

MongoDB sorts the input array based on the sortBy value. The following table provides examples of different sort options:

input

sortBy

Sorted input

[ 8, 3, 1, 10]

1

[1, 3, 8, 10]

[ 8, 3, 1, 10]

-1

[10, 8, 3, 1]

[
  { a: 1, b: 1 },
  { a: 2, b: 2 },
  { a: 2, b: 1 }
]

{ a: 1, b: 1 }

[
  { a: 1, b: 1 },
  { a: 2, b: 1 },
  { a: 2, b: 2 }
]

Input Values

The input field must resolve to an array. If you specify an input that is not an array, MongoDB errors.

Example

The following example uses the movies collection from the sample_mflix sample dataset. For details on how to load this dataset into your deployment, see Load the sample dataset.

The movies collection contains documents that resemble the following example:

{
   _id: ObjectId('573a1396f29313caabce4a9a'),
   year: 1972,
   genres: [ 'Crime', 'Drama' ],
   title: 'The Godfather',
   cast: [ 'Marlon Brando', 'Al Pacino', 'James Caan', 'Richard S. Castellano' ],
   directors: [ 'Francis Ford Coppola' ],
   runtime: 175,
   ...
}

The following aggregation pipeline uses $top on the cast array to return the first cast member in alphabetical order for a specified movie:

db.movies.aggregate([
   {
      $match: { title: "The Godfather" }
   },
   {
      $project: {
         _id: 0,
         title: 1,
         firstCastMemberAlphabetically: {
            $top: {
               sortBy: 1,
               input: "$cast"
            }
         }
      }
   }
])

[
   {
      title: 'The Godfather',
      firstCastMemberAlphabetically: 'Al Pacino'
   }
]

In this example, $top sorts the existing cast array in ascending alphabetical order and returns the first value.

Back

$toObjectId

$topN